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Topic: Super Easy Math Problem! EASY 10 points!?**Question:**
Larry, Curly, and Mo entered a math contest on which the problems varied in difficulty. The easiest problems were worth two points each, the medium ones three points each, and the brainbusters seven points each. Each of them solved the same number of problems correctly and ended up with exactly thirty points, although none of them solved the same number of any type of problem. How many problems did each solve?

July 19, 2019 / By Eliot

They all answered 10 problems. 1= 8 easy and 2 brainbusters 2= 10 medium 3= 4 easy, 5 medium, and 1 brainbuster

👍 194 | 👎 3

Did you like the answer? 1. 2x - y =6 x+y = -3 solve for y in second equation... y=-3-x plug y into first equation 2x - (-3-x) = 6 2x +3 + x=6 3x=3 x=1 plug x value into second equation y=-3-(1) y=-4 x=1, y =-4 you can check it on your own... it works 2. 2x+y=8 y=x-7 plug second equation(y) into first 2x + (x-7)=8 3x-7=8 3x=15 x=5 plug 5 into second equation as x to find y y=(5)-7 y=-2 so x=5, y=-2 yet again, it works... so you can check it (just plug both numbers into original equation 3. 1/2x + 1/3 = 5 1/4+y=10 so... y=10-1/4 y=40/4(really 10) - 1/4 y = 39/4 1/2x+1/3=5 1/2x=5-1/3 1/2x=15/3(really 5)-1/3 1/2x = 14/3 x = 28/3 so x = 28/3 , y = 39/4 4. -2x+y=0 5x+3y=-11 solve for y in first equation y = 2x plug y into second equation 5x + 3(2x)=-11 5x+6x=-11 11x=-11 x=-1 plug x into first equation y = 2(-1) y = -2 so x = -1 & y = -2 (it works i know) hope that helps

1. y=2x-6 x+(2x-6)=-3 3x=3 x=1 if x=1 then 1+y=-3 y=-4 2. 2x+(x-7)=8 3x-7=8 3x=15 x=5 if x=5 then y=5-7 y=-2 3. x=(4&2/3)*2 x=9&1/3 y=9&3/4 4. y=2x 5x+3(2x)=-11 5x+6x=-11 11x=-11 x=-1 if x=-1 then y=-2

nicely, you may desire to characteristic up the numbers of hens, pigs, sheep, horses, and cows. then you definitely take the variety of the animal you're pertaining to and divide it by way of the full extensive type you in elementary terms got here upon. Say, for area a, you're taking the full variety of pigs (12) and divide it by way of the full variety of animals (10 hens + 12 pigs + 10 sheep + 8 horses + 6 cows) to get your fraction. You do a similar for c. For b, you upload the numbers of sheep (10) and horses (8) and take that extensive type, 18, out of the full variety of animals. and then for d, you positioned the fractions so as from the smallest fraction to the biggest one. because of the fact you're utilising the numbers of pigs (12), hens/sheep (18), and cows (6), the cow fraction will finally end up being smallest, observed by way of pigs and then hens/sheep. yet ensure you positioned the fractions and not those unique numbers! sturdy success :)

1. 12 of 2 points 2of 3 points 2. 7 of 3 oints 3 of 3 points 3. 10 of 3 points

👍 80 | 👎 1

Billys Candy = 10 4 kids with 2 pieces each: kid 1 = 2 kid 2 = 2 kid 3 =2 kid 4= 2 The equation becomes: Billys Candy + (# of kids multiplied by number of pieces per kid) = amount of original candy. Im not going to solve it for you - but I hope this explains how to get the answer (PS you learn nothing by cheating through the internet dear, and will be ****** if you continue looking for answers via websites when you go to high school or college, take the time to learn your lessons if you want a well paying job; and Im not a lecturing parent - Im a college student telling you how it is) good luck!

Let x be the number of candy in total. (x-10)/4=2 x-10=8 x=18 Therefore, she started with 18 pieces of candy.

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