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# Super Easy Math Problem! EASY 10 points!?

Topic: Super Easy Math Problem! EASY 10 points!?
July 19, 2019 / By Eliot
Question: Larry, Curly, and Mo entered a math contest on which the problems varied in difficulty. The easiest problems were worth two points each, the medium ones three points each, and the brainbusters seven points each. Each of them solved the same number of problems correctly and ended up with exactly thirty points, although none of them solved the same number of any type of problem. How many problems did each solve?

## Best Answers: Super Easy Math Problem! EASY 10 points!?

Chauncey | 3 days ago
They all answered 10 problems. 1= 8 easy and 2 brainbusters 2= 10 medium 3= 4 easy, 5 medium, and 1 brainbuster
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Originally Answered: Need help with math problem?! Very easy 10 points!?
1. 2x - y =6 x+y = -3 solve for y in second equation... y=-3-x plug y into first equation 2x - (-3-x) = 6 2x +3 + x=6 3x=3 x=1 plug x value into second equation y=-3-(1) y=-4 x=1, y =-4 you can check it on your own... it works 2. 2x+y=8 y=x-7 plug second equation(y) into first 2x + (x-7)=8 3x-7=8 3x=15 x=5 plug 5 into second equation as x to find y y=(5)-7 y=-2 so x=5, y=-2 yet again, it works... so you can check it (just plug both numbers into original equation 3. 1/2x + 1/3 = 5 1/4+y=10 so... y=10-1/4 y=40/4(really 10) - 1/4 y = 39/4 1/2x+1/3=5 1/2x=5-1/3 1/2x=15/3(really 5)-1/3 1/2x = 14/3 x = 28/3 so x = 28/3 , y = 39/4 4. -2x+y=0 5x+3y=-11 solve for y in first equation y = 2x plug y into second equation 5x + 3(2x)=-11 5x+6x=-11 11x=-11 x=-1 plug x into first equation y = 2(-1) y = -2 so x = -1 & y = -2 (it works i know) hope that helps
Originally Answered: Need help with math problem?! Very easy 10 points!?
1. y=2x-6 x+(2x-6)=-3 3x=3 x=1 if x=1 then 1+y=-3 y=-4 2. 2x+(x-7)=8 3x-7=8 3x=15 x=5 if x=5 then y=5-7 y=-2 3. x=(4&2/3)*2 x=9&1/3 y=9&3/4 4. y=2x 5x+3(2x)=-11 5x+6x=-11 11x=-11 x=-1 if x=-1 then y=-2
Originally Answered: Need help with math problem?! Very easy 10 points!?
nicely, you may desire to characteristic up the numbers of hens, pigs, sheep, horses, and cows. then you definitely take the variety of the animal you're pertaining to and divide it by way of the full extensive type you in elementary terms got here upon. Say, for area a, you're taking the full variety of pigs (12) and divide it by way of the full variety of animals (10 hens + 12 pigs + 10 sheep + 8 horses + 6 cows) to get your fraction. You do a similar for c. For b, you upload the numbers of sheep (10) and horses (8) and take that extensive type, 18, out of the full variety of animals. and then for d, you positioned the fractions so as from the smallest fraction to the biggest one. because of the fact you're utilising the numbers of pigs (12), hens/sheep (18), and cows (6), the cow fraction will finally end up being smallest, observed by way of pigs and then hens/sheep. yet ensure you positioned the fractions and not those unique numbers! sturdy success :)

Alvred
1. 12 of 2 points 2of 3 points 2. 7 of 3 oints 3 of 3 points 3. 10 of 3 points
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