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CAn aNyOnE HeLp Me SoLvE THiS EqUaTiOn?

CAn aNyOnE HeLp Me SoLvE THiS EqUaTiOn? Topic: CAn aNyOnE HeLp Me SoLvE THiS EqUaTiOn?
July 18, 2019 / By Aliah
Question: 1) 4sqrt3 + 2sqrt3 - 6sqrt3 2) -sqrt128 3) sqrt21 * sqrt3 4) 20sqrt50 / 4sqrt2 5) 14sqrt150 / 7sqrt2 6) 3sqrt2 + 2sqrt32 7) 2sqrt45 8) 5sqrt8 * 7sqrt3 9) 3sqrt5 + 6sqrt2 - 3sqrt2 + sqrt5 10) (5+sqrt2) (6+sqrt2)
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Best Answers: CAn aNyOnE HeLp Me SoLvE THiS EqUaTiOn?

Tyrone Tyrone | 8 days ago
1) They all have the same sqrt term so you can simply add them together:4 + 2 - 6 = 0 2) You have to simplify sqrt 128 first. sqrt 128 = sqrt 16 x 8. The sqrt of 16 is four so it becomes 4sqrt 8. sqrt 8 = sqrt 4 x 2. The sqrt of 4 is 2 so it becomes 8sqrt 2. Then just add the negative sign so it's -8sqrt2. 3) Multiply them together first since you cannot simplify them as of now. You should get sqrt63 as your answer. sqrt 63 = sqrt 9 x 7. The sqrt of 9 is 3 so it becomes 3sqrt7. 4) 20 / 4 is 5 so you have 5sqrt 50 / sqrt 2. sqrt 50 = sqrt 25 x sqrt 2. The sqrt of 25 is 5 so it becomes 25sqrt 2 / sqrt 2. Cancel out the sqrt 2's and you are left with 25. 5) 14 / 7 is 2 so you have 2sqrt 150 / sqrt 2. sqrt 150 = sqrt 25 x 6. The sqrt of 25 is 5 so now you have 10sqrt 6 / sqrt 2. Now we cannot have a radical in the denominator so we multiply the top and bottom of the fraction by sqrt 2 so we now have 10sqrt 12 / 2. 10 / 2 is 5 so now it's 5sqrt 12. sqrt 12 = sqrt 4 x 3. The sqrt 4 is 2 so when fully simplified it's 10sqrt 3. I showed you how to do half of the problems, try to see if you can do the rest since practice makes perfect.
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Tyrone Originally Answered: Graphing equation question? how would solve this linear equation?
2x + 3(11/3) = 12 3/1 * 11/3 = 33/3 When multiplying, just multiply across, numerator to numerator and denominator to denominator. (I know I put a 1 under the 3, all whole numbers have a 1 under them) (example : 3/1 = 3) or ( lets say 5 in fraction form is 5/1 ) (Another fraction example 2/5 * 3/4 mult across and you get 2 * 3 = 6 and 5 * 4 = 20 answer 6/20 then, simplify and get 3/10) Now simplify 33/3 = 11 2x + 11 = 12 Now subtract 11 from both sides. and you get 2x = 1 2x = 1 Now divide 2 on both sides and you get x = 1/2 ordered pair is (1/2 , 11/3)

Rik Rik
I'll give you a tip for next time : Dont throw 10 questions up all at once. Try ask at most 3 per question. Anyway to get you started : 1) To make this easier for you let sqrt3 = x => 4x + 2x - 6x = 0x => 0sqrt3 = 0
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Merv Merv
With addition and subtraction, you can't combine terms unless they are alike. For examples, #1 is all sqrt3, so you just add and subtract coefficients for an answer of 0. For the rest, find a calculator that gives square root. For examples, the sqrt of 128 is 8sqrt2.
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Jordon Jordon
homework huh? u can't get smarter if u don't do it urself. and lol, its okay, i do things like this sometimes too. i can't help though. im only 12 yrs old and that sure looks mighty hard...LOL
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Jordon Originally Answered: Solve this equation; like a quadratic equation.?
With substitution it becomes a quadratic. Let u = w² and rewrite as: u² + 7u - 18 = 0 (u+9)(u-2) = 0 u = -9 and 2 = w² w = ±3i and ±√2

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