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# EASY word problems! 10 points for BEST answer! Easy points! Mulitiple choice?

Topic: EASY word problems! 10 points for BEST answer! Easy points! Mulitiple choice?
July 18, 2019 / By Brannon
Question: I need the answers to these questions, I will return the favor for anything but math. You may contact me at my profile for messanger or email, or princessavero1 at yahoo . com .Thank you so much! =) If you need any help with the info provided plz contact me at the info. given. Thanks! =) I'm willing to return the favor!!!!!!!! 1. Joe is 5 years older than Sally. In 15 years Joe will be 3 times as old as Sally is now. How old is Sally now? Hint: Write Joe's age now in terms of Sally's age now. Then write Joe's age in 15 years using the expression you just wrote for Joe's age now. Then using S for Sally's age now, write the equation in only one variable "S" and solve it. a) 2 b) 10 c) 15 d) 30 e) 45 2. The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 5. Now you have to write the equation and solve it. a) 16 b) 7 c) 8 d) 21 e) 24 3. 5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer? a) 10 b) 12 c) 14 d) 16 e) 18 4. 15 more than 4 times a number is 6 more than 5 times the number. Find the number. a) 21/9 b) -9 c) -9/21 d) 2 e) 9 5. Martha and Sally had lunch together on Tuesday. Sally paid \$2 more than Martha. If the total bill was \$5.64, how much did Sally pay for her lunch? a) \$1.82 b) \$2.00 c) \$3.64 d) \$3.82 e) \$7.64 6. Bob paid 3 less than Tim for his lunch at a local pizza parlor. Together they spent \$7.80. How much did Bob spend for his lunch? a) \$2.40 b) \$4.50 c) \$4.80 d) \$5.40 e) \$8.40 7. There were 6 more women on a committee than men. If the committee was made up of 30 people, how many men were on the committee? a) 6 b) 12 c) 24 d) 30 e) 36 8. Three consecutive integers have the sum of 153. What is the second integer? a) 50 b) 51 c) 52 d) 53 e) 54 9. The sum of 3 consecutive even integers is 54. What is the first consecutive integer? a) 13 b) 14 c) 15 d) 16 e) 17 10. An airplane flies at a rate of 356 km/h. If the plane travels a total distance of 1424 km, how long was it in the air? a) 3.56 hours b) 4 hours c) 4.24 hours d) 5 hours e) 14.2 hours

## Best Answers: EASY word problems! 10 points for BEST answer! Easy points! Mulitiple choice?

Originally Answered: Does this sentence make sense?! Easy points only have to put one word answer! :D?
\$675 (total tickets) \$21 , x (# of \$21 tickets) \$27 , y (# of \$27 tickets) x + y = 29 y = 29 - x now we can use one variable. (easier) 21x - 27y = 675 substitute y 21x + 27(29-x) = 675 21x + 783 - 27x = 675 -6x = 675 - 783 -6x=-108 6x=108 x=18 y = 29 - 18 y = 11 They bought 18 of \$21 and 11 of \$27
Originally Answered: Does this sentence make sense?! Easy points only have to put one word answer! :D?
Don't worry, it is actually a really easy question. Here goes: it's a system of equations right? Therefore, you will need TWO equations for this one since we have two different ticket prices. For tickets with the price of \$21 I will give it the variable "x" and for tickets with the price of \$27, I will give it the variable of "y" since these two are the easiest to use. Here are my TWO equations: 1.) 21x + 27y= 675 (multiply the number of tickets to there respectful price and then add them together to get the total cost of all the tickets, which is why it looks like i showed it above. We still don't know how many tickets were sold for \$21 nor those sold at \$27 so I will use the assigned variables I established earlier. We do know however, that between both, they make total of \$675.) 2.) x+y=29 (We don't know how many of each tickets were sold, but we do know that between both sells, the baseball game had 29 tickets sold, which is why it looks like that equation.) Now comes the tricky part: We can't solve both unknown pieces of information, so we need to get rid of one variable in both equations. I will use the ELIMINATION METHOD to do so. It doesn't matter which one of the two you pick to get rid of. I will choose to eliminate "21x". To do this, I will multiply one equations by a -21! like this: -21(x+y=29) It doesn't matter which one you decide to multiply. NOTE: a negative and positive cancel each other out. The new result ends up giving you: 1.) 21x + 27y= 675 2.) -21x + -21y= -609 Next, you will have to combine like terms using both equations. I see that we can cancel the positive 21x and the negative 21x. If we had positive 27y with -21y, we are left with positive 6y. Finally we have 675 + -609. After we combine them, we are left with positive, so your new and only equation reads: 1.) 6y=66 (Now we do simple algebra by dividing 66 by 6. So now we know that y= 11. So now we have the number of tickets purchased at the price of \$27.) Substitute 11 into the "y" of the second equation and you get this: x+ (11)= 29 (You should know what to do from here and you should end up with this: x=18, y=11 Simple huh?

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