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# Solve the problem (word problem)?

Topic: Solve the problem (word problem)?
July 19, 2019 / By Jehiel
Question: I wasn't sure of how to type some of the symbols in the problem,so I made a copy of how it exactly looks on my paper.Picture link is below. http://i55.tinypic.com/2a7hc05.jpg

## Best Answers: Solve the problem (word problem)?

Garth | 9 days ago
1/R = 1/R1 + 1/R2 + 1/R3 1/R = (R2R3)/(R1R2R3) + (R1R3)/(R1R2R3) + (R1R2)/(R1R2R3) 1/R = (R1R2 + R1R3 + R2R3)/(R1R2R3) R(R1R2 + R1R3 + R2R3) = R1R2R3 R = R1R2R3/(R1R2 + R1R3 + R2R3) Hope that helps :)
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Originally Answered: Word Problem: Solve the Problem ( Elementary Algebra College Class)?
Using d=rt, in 2 hours Eden will have traveled 6 miles north and Madison will have traveled 8 miles west. Using the Pythagorean theorem, solve for the hypothenuse. 8^2 + 6^2 = c^2 64 + 36 = c^2 100 = c^2 c = 10 The distance will be 10 miles.
Originally Answered: Word Problem: Solve the Problem ( Elementary Algebra College Class)?
So you're gonna make a triangle. Eden goes 6 miles (2x3). That's your d=rt. The rate they go is how many miles per hour, the time obviously 2 hours. Madison goes 8 (2x4). So imagine a right triangle, where madison's distance is the bottom, and edens's the other side. You need to find the hypontenuse, use the pythagorean theorem. A^2 +b^2=c. So 6^2 + 8^2=100. Square root of 100 is 10. That's your answer. 10miles.
Originally Answered: Word Problem: Solve the Problem ( Elementary Algebra College Class)?
so which you're gonna make a triangle. Eden is going 6 miles (2x3). it is your d=rt. the cost they pass is what proportion miles per hour, the time for specific 2 hours. Madison is going 8 (2x4). So think of of a suitable triangle, the area madison's distance is the backside, and edens's distinctive factor. you will possibly be able to desire to need to discover the hypontenuse, use the pythagorean theorem. A^2 +b^2=c. So 6^2 + 8^2=one hundred. sq. root of one hundred is 10. it is your answer. 10miles.

Devil
The common denominator is R1 * R2 * R3. You pretty much have to assume that they share no common factor. 1/r = R2*R3 + R1*R3 + R2*R3 . . . . .================= . . . . . . . . . . . .R1*R2 * R3 Now flip both sides of the equation. r = R1 * R2 * R3 . . .========== . . . R2*R3 + R1*R2 + R1*R3 You could try it with something that you know the answer to like R1=R2=R3 = 300 ohms. You might know that when all three are equal, the result is R1/3 = 100 in this case. R = (300 * 300 * 300)/(300*300 + 300*300 + 300*300) You could do this without cancellation. R = (27000000)/(90000 + 90000 + 90000) = 27000000/(270000) = 100
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Originally Answered: Word Problem: Solve the Problem ( Elementary Algebra College Class)?
let the speed of boat be x is still water. then speed downstream is x+4 and upstream is x-4 now time=dist/speed using the above formula 40/(x+4) = 20/(x-4) since time is same in both cases. calculate for x. answer is 12
Originally Answered: Word Problem: Solve the Problem ( Elementary Algebra College Class)?
time= distance/ speed go down the speed is s+4 goo upstream speed is s-4 same time 40/s+4 =20/s-4 from the equation speed= 12 miles here you go

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