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Topic: Algebra help! Solve each equation for x.?**Question:**
So, I don't remember how to do this! We have to solve each equation for x and state any restrictions. So what exactly does that mean- state any restrictions?
Here are the problems.
1. ax - bx = 2a
2. x/c + c = 4c
3. (x-5)/a + 1 = b
4. ax + 2 = bx + c

July 19, 2019 / By Haven

The restriction is 0 cannot be in any denominators because that would cause the expression to be undefined. 1) ax - bx = 2a x(a - b) = 2a x = 2a/(a - b) The restriction is a - b does not equal 0. 2) x/c + c = 4c x/c = 3c x = 3c^2 There are no restrictions. 3) (x - 5)/a + 1 = b (x - 5)/a = b - 1 x - 5 = ab - a x = ab - a + 5 There are no restrictions. 4) ax + 2 = bx + c ax - bx = c - 2 x(a - b) = c - 2 x = (c - 2)/(a - b) The restriction is a - b does not equal 0.

👍 228 | 👎 10

Did you like the answer? x/2 + x/3 = (5x + 2)/6 first, multiply by 6 to eliminate the denominators 3x + 2x = 5x + 2 subtract 5x from both sides 0 = 2 This is impossible, so there is no solution.

1. ax - bx =2a x(a-b)=2a x=2a/a-b 2.x/c + c=4c x/c=3c x=3c^2 3.(x-5)/a + 1 = b (x-5+a)/a=b x-5+a=ab x=ab-a+5 4. ax + 2 = bx + c ax-bx=c-2 x(a-b)=c-2 x=(c-2)/(a-b)

👍 90 | 👎 3

Qu 1 ( a - b ) x = 2a x = 2a / ( a - b )_______a must not = b Qu 2 x/c = 3c x = 3 c ² Qu 3 (x - 5)/a = b - 1 x - 5 = a (b - 1) x = 5 + a (b - 1) Qu 4 (a - b) x = c - 2 x = ( c - 2 ) / ( a - b )______a must not = b

👍 81 | 👎 -4

3x^2+12x=0 you could ingredient out a three 3(x^2+4x)=0 now the x [you do not ought to do it unexpectedly 3x(x+4)=0 x^-7x=8 is that think to be x^2-7x=8 ? x^2-7x-8=0 now you choose 2 numbers whose product is -8 and sum is -7 (x-8)(x+a million)=0 it receives greater trouble-free with prepare

👍 72 | 👎 -11

Additional details Banquet cost is $85 plus $15 for each person attending let y be the cost of the banquet for x people attending. y = $85 + $15x for 78 people x = 78 y = $85 + $15(78) y = $85 + $1170 y = $1,255

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