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Topic: 10 points. Can you help me with this easy math for my daughter in 5th grade? I forgot how to do it!?**Question:**
You deposit $4000 into a savings account. The account earns 2.75% simple interest. How long will it take to earn $220 in interest?
Thank you! Please give me the answer AND how to solve if you can so I can actually help my daughter.

June 16, 2019 / By Alyssia

I'll assume the interest's per year. Interest = Principal * Time * Rate 220 = 4000 * x * 0.0275 Since time is unknown, I used x x = 2 2 years Clear explanation can be seen here. http://www.tutorvista.com/math/solve-sim...

👍 272 | 👎 2

Did you like the answer? Ok. To divide fractions, you multiply by what's called the "reciprocal" which is a fancy word that means "the fraction, but with the two numbers switched with each other." So in this case: 1/2 divided by 2/5 is the same as 1/2 multiplied by 5/2 And then multiply both top numbers by each other and both bottom numbers by each other: 1x5/2x2 Which equals 5/4

You'd do 2.75% of $4000, which is 0.0275 x 4000 = $110 interest each year, then divide 220 by 110 getting 2 years.

👍 120 | 👎 -5

4000/100 x 2.75 = 110 If the interest is 2.75 per day than its 2 days, or per week than its 2 weeks and so forth.

👍 119 | 👎 -12

This is how i did it. 4000 * 2,75% = 4110 4110 * 2,75% = 4223,025 1st year Intrest $110 2 year intrest $113.025 So i would say that it takes around 2 years.

👍 118 | 👎 -19

a) You have two variables, the number of cheap sheets and the number of expensive sheets. You have the maximum total price, so it's a simple calculation Price of cheap * # of cheap + Price of expensive * # of expensive ≤ $1.50 To make the inequality with only one variable, you need to express the one variable as a function of the other. You can do this because you know the total number or sheets, so you can express it like so: t : # of cheap sheets s : # of expensive sheets T : Total # of sheets (given as 12) t + s = T t + s = 12 s = 12-t Now, simply put the numbers given in the problem into the inequality: $0.08 * t + $0.15 * s ≤ $1.50 And replace the one variable with the equal term above: $0.08 * t + $0.15 * (12-t) ≤ $1.50 b) Just solve the inequality: $0.08 * t + $0.15 * (12-t) ≤ $1.50 $0.08*t - $0.15*t + $1.8 ≤ $1.50 $-0.07*t ≤ $-0.3 t ≥ 4.3 So, five or six sheets of the cheap paper

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