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# 10 points. Can you help me with this easy math for my daughter in 5th grade? I forgot how to do it!?

Topic: 10 points. Can you help me with this easy math for my daughter in 5th grade? I forgot how to do it!?
June 16, 2019 / By Alyssia
Question: You deposit \$4000 into a savings account. The account earns 2.75% simple interest. How long will it take to earn \$220 in interest? Thank you! Please give me the answer AND how to solve if you can so I can actually help my daughter.

## Best Answers: 10 points. Can you help me with this easy math for my daughter in 5th grade? I forgot how to do it!?

Vincent | 2 days ago
I'll assume the interest's per year. Interest = Principal * Time * Rate 220 = 4000 * x * 0.0275 Since time is unknown, I used x x = 2 2 years Clear explanation can be seen here. http://www.tutorvista.com/math/solve-sim...
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Ok. To divide fractions, you multiply by what's called the "reciprocal" which is a fancy word that means "the fraction, but with the two numbers switched with each other." So in this case: 1/2 divided by 2/5 is the same as 1/2 multiplied by 5/2 And then multiply both top numbers by each other and both bottom numbers by each other: 1x5/2x2 Which equals 5/4

Royal
You'd do 2.75% of \$4000, which is 0.0275 x 4000 = \$110 interest each year, then divide 220 by 110 getting 2 years.
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Morgan
4000/100 x 2.75 = 110 If the interest is 2.75 per day than its 2 days, or per week than its 2 weeks and so forth.
👍 119 | 👎 -12

Keelan
This is how i did it. 4000 * 2,75% = 4110 4110 * 2,75% = 4223,025 1st year Intrest \$110 2 year intrest \$113.025 So i would say that it takes around 2 years.
👍 118 | 👎 -19

Originally Answered: SUPER EASY MATH QUESTION 10 POINTS QUICKLY AND EASY!?
a) You have two variables, the number of cheap sheets and the number of expensive sheets. You have the maximum total price, so it's a simple calculation Price of cheap * # of cheap + Price of expensive * # of expensive ≤ \$1.50 To make the inequality with only one variable, you need to express the one variable as a function of the other. You can do this because you know the total number or sheets, so you can express it like so: t : # of cheap sheets s : # of expensive sheets T : Total # of sheets (given as 12) t + s = T t + s = 12 s = 12-t Now, simply put the numbers given in the problem into the inequality: \$0.08 * t + \$0.15 * s ≤ \$1.50 And replace the one variable with the equal term above: \$0.08 * t + \$0.15 * (12-t) ≤ \$1.50 b) Just solve the inequality: \$0.08 * t + \$0.15 * (12-t) ≤ \$1.50 \$0.08*t - \$0.15*t + \$1.8 ≤ \$1.50 \$-0.07*t ≤ \$-0.3 t ≥ 4.3 So, five or six sheets of the cheap paper

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