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Topic: Confusing algebra word problems?**Question:**
Am I the only person who doesn't understand how to solve algebra word problems? Grr! I will learn it!

July 20, 2019 / By Amie

It starts out simple and the fractions make it harder. distance = rate * time Eq 1, d= 80 km/hr * (t + 1/30) Eq 2 d = 90 km/hr * (t - 1/60) the distance is the same, the time part is how long it took you to get to the air port set eq1 = eq2 so 80 * (t + 1/30) = 90 * (t - 1/60) I am going too skip some steps, you can work on simplification 80t + 80/30 = 90t - 90/60 we solve for t 10t = 80/30 + 90/60 t= 125/300 hrs plug in to equation 1 d = 80 * (125/300 + 1/30) do the math d= 36 km

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Did you like the answer? Question 1: Let x = width Length = 3+2x Parameter = 48 = 2(Length) + 2(Width) So: 48 = 2(3+2x) + 2(x) 48 = 6 + 4x + 2x 48-6 = 6x 42 = 6x 7 = x or x=7 Your answer. Question 2: Integer 1 = x Integer 2 = x+2 Interger 3 = (x+2) + 2 or (x+4) Based on info provided: 5x = 14 + 3(x+2) Solving for x: 5x = 14 + 3x + 6 5x - 3x = 14 + 6 2x = 20 x = 10 Integer 3 = x+ 4 so therefore it equals 14. Question 3: 15 + 4x = 6 + 5x 4x - 5x = 6 - 15 -x = -9 x = 9

1) let x be the width, so length is 2x + 3 the perimeter is the sum of the four sides of the area. therefore: x + (2x + 3) + x + (2x +3) or 2x + 2(2x +3) = 48ft answer: x = 7ft 2) let x be the first even integer, the second even integer is (x+2) and the third integer is (x + 2 + 2) or (x + 4) so that: 5x = 3 (x + 2) +14 x = 10 therefore the third consecutive even integer is 14. 3) let x be the number 4x + 15 = 5x + 6 x = 9

Did the teacher or book give you any examples as guides for solving them? That is a good way to develop a feel for working them. Maybe give some specific ones which are causing you trouble?

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First, understand the problem. Write down, what are the given and the required. Understand the wording of the problem. Clear your mind. Use common sense.

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You have to learn how to translate English into "Mathese". The word :"product" (and often just the word "of") means multiplication. Any form of the verb "to be" (such as is, was, were, be, being, been, and so on) generally means an equals sign. In your case: 1) Let x and y be the numbers. (I'm assuming that the second time the number is mentioned, you mean it to be a different number). The product of (multiplication) three more (addition) than a numbers times two less (subtraction) than another number is (equals) fourteen. (x + 3)(y - 2) = 14 2) Let x be one integer. If they are consecutive odd integers, then they differ by 2, so the other would be x + 2. The sum (addition) of the squares (obvious) of two consecutive odd positive integers is (equals) 202. x^2 + (x + 2)^2 = 202 That should give you enough to get the last one.

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