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A little help on a Math question plz?

A little help on a Math question plz? Topic: A little help on a Math question plz?
June 16, 2019 / By Anetta
Question: Ok here's the problem and please if u want show ur work =): Mercury's surface temp has a range of 600 degrees Celsius. This range is the broadest of any planet int he solar system. If the lowest temp on Mercury's surface is -173 degrees celsius, write and solve an equation to find the highest temp.
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Best Answers: A little help on a Math question plz?

Wilburn Wilburn | 5 days ago
Let H be the highest temperature and L be the lowest temperature, both in degrees Celsius.. The equation would be H = L + 600. We can substitute -173C for L, giving us H = -173 + 600. Adding these two numbers gives us (-173 + 600 = 600 - 173) 427C as the highest temperature.
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Wilburn Originally Answered: Homework math question; I don't understand the math question can someone help? :-)?
Remark. "ten hundred" does not make sense. Recipe to round a number: if you want round to the nearest 10, you look at the last digit. from 0 to 4, replace by zero from 5 to 9, replace by zero AND add 1 to the second digit. rounding(307,125) = 307,130 rounding(950,493) = 950,490 if you want round to the nearest 100, you look at the last 2 digits. from 0 to 49, replace by zeros from 50 to 99, replace by zeros AND add 1 to the 3rd digit. rounding(11,071,394) = 11,071,400 if you want round to the nearest 1000, you look at the last 3 digits. from 0 to 499, replace by zeros from 500 to 999, replace by zeros AND add 1 to the 4th digit. rounding(15,700,917) = 15,701,000 rounding(670,982) = 671,000
Wilburn Originally Answered: Homework math question; I don't understand the math question can someone help? :-)?
You first have to know the names of each numbers "place" in the whole number. Using the first one: 1 is in the tens place, 1 is in the hundreds place, (there is no "ten hundred" place) 6 is in the thousand place, 8 is in the ten thousand place, 4 is in the hundred thousand place. To round off, look at the number just to the right of the place you want to round off to. If that number is less than five, change it and all the numbers to it's right to zeros. If it is five or more, change the place number to one higher and all the numbers to it's right should be zeros.
Wilburn Originally Answered: Homework math question; I don't understand the math question can someone help? :-)?
(a) nearest ten (b) nearest hundred (c) nearest ten hundred (d) nearest thousand (e) nearest ten thousand (f) nearest hundred thousand 486,112 (a) 486,110 (b) 486,100 (c) 486,000 (d) 486,000 (e) 490,000 (f) 500,000 307,125 (a) 307,130 (b) 307,100 (c) 307,000 (d) 307,000 (e) 310,000 (f) 300,000 670,982 (a) 670,980 (b) 671,000 (c) 671,000 (d) 671,000 (e) 670,000 (f) 700,000 950,493 (a) 950,490 (b) 950,500 (c) 950,000 (d) 950,000 (e) 900,000 (f) 1,000,000 1,217,157 (a) 1,217,160 (b) 1,217,200 (c) 1,217,000 (d) 1,217,000 (e) 1,220,000 (f) 1,200,000 3,471,908 (a) 3,471,910 (b) 3,471,900 (c) 3,472,000 (d) 3,472,000 (e) 3,470,000 (f) 3,500,000 6,192,347 (a) 6,192,350 (b) 6,192,300 (c) 6,192,000 (d) 6,192,000 (e) 6,190,000 (f) 6,200,000 9,041,071 (a) 9,041,070 (b) 9,041,100 (c) 9,041,000 (d) 9,041,000 (e) 9.041,000 (f) 9,000,000 11,071,394 (a) 11,071,390 (b) 11,071,400 (c) 11,071,000 (d) 11,071,000 (e) 11,070,000 (f) 11,100,000 15,700,917 (a) 15,700,920 (b) 15,700,900 (c) 15,701,000 (d) 15,701,000 (e) 15,700,000 (f) 15,700,000 20,378,956 (a) 20,378,960 (b) 20,379,000 (c) 20,379,000 (d) 20,379,000 (e) 20,380,000 (f) 20,400,000 27,109,114 (a) 27,109,110 (b) 27,109,100 (c) 27,109,000 (d) 27,109,000 (e) 27,110,000 (f) 27,100,000 37,400,908 (a) 37,400,910 (b) 37,400,900 (c) 37,401,000 (d) 37,401,000 (e) 37,400,000 (f) 37,400,000 54,132,704 (a) 54,132,700 (b) 54,132,700 (c) 54,133,000 (d) 54,133,000 (e) 54,130,000 (f) 54,100,000 65,119,099 (a) 65,119,100 (b) 65,119,100 (c) 65,119,000 (d) 65,119,000 (e) 65,120,000 (f) 65,100,000 90,145,912 (a) 90,145,910 (b) 90,145,900 (c) 90,146,000 (d) 90,146,000 (e) 90,150,000 (f) 90,100,000 *ten hundred = thousand

Sawyer Sawyer
Do you remember what range means? The lower limit is -173 so the upper limit must be 600 higher than that. It doesn't really need an equation to solve it but since range is defined as the difference between the upper limit and lower limit, you could write this as x - (-173)=600 and solve for x.
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Sawyer Originally Answered: My question involves the math mentioned in the 1994 movie Stargate. I want to know what math theory they used?
You're talking about two different things. Pythagoras's theorem is about distance between two points. Stargate was dealing with the location (not distance) of a point. The concept used to indicate the location of a planet in Stargate is correct, though somewhat redundant. We need only three points (and maybe a fourth point for orientation) to describe the location of a point in space, not six. Consider a point in a two dimensional plane. One requires only two points - or "coordinates" would the better word - to describe it's location: one to indicate its position along the horizontal, and a second to indicate its position along the vertical. Examples of this in real life would be latitude and longitude coordinates on a map, or the letters and numbers in a game of Battleship. In space, similarly, you'd need three coordinates to describe the location of point. Having said that, however, the one thing lacking in space is orientation. Going back to the 2D example of a map, we have established orientation based on the Earth's rotational axis and we get North, South, East, and West. We don't have that in space. There is no North or South in space. That's why we need a fourth point - a point to establish orientation. Perhaps one day in the distant future our space faring descendants will decide a system of orientation based on the solar system or the galaxy, and that fourth point will no longer be necessary. EDIT: Come to think of it, we sometimes do use a three coordinate system to describe our location. GPS devices will show you latitude and longitude, but some of the more sophisticated ones will also give you a third coordinate - your elevation. That tells you your position not just in 2D but in 3D. Elevator/building floor levels are the simpler version of the same thing. ===== ===== ===== ===== ===== EDIT: I forgot to explain Pythagoras's Theorem, though other respondents have covered most of it. The theorem basically states that the length of a right triangle's hypotenuse is equal to the square-root of the sum of the squares of the other two sides. Assuming we know the length of sides A and B the theorem is abbreviated: Hypotenuse =sqrt((A^2)+(B^2)) The theorem can be used to calculate the distance between two points. Let's say we're playing Battleship, and there is a peg at B2 and a peg at H10. The horizontal displacement of the second peg from the first peg is 6 blocks (B to H). The vertical displacement is 8 blocks (2 to 10). Effectively 6 and 8 are the lengths of sides A and B. The distance can then be calculated as such: Distance =sqrt((6^2)+(8^2)) =sqrt(36+64) =sqrt(100) =10 That's a distance of 10 blocks between the pegs. Pythagoras's Theorem, by the way, also works in 3D (or 4D, 5D, and so on). The formula to calculate the diagonal of a cube or rectangular cuboid, for example, would be: Diagonal =sqrt((A^2)+(B^2)+(C^2))
Sawyer Originally Answered: My question involves the math mentioned in the 1994 movie Stargate. I want to know what math theory they used?
Okay -- bear in mind that Stargate (great movie) is fiction. But the science is a projection of some ideas found in real science. BTW -- we are actually talking physics. Math is the "language" o physics. The star gate was supposed to be a "wormhole" That is a nickname for an Einstein-Rosenberg bridge. These two physicists pointed out decades ago that the mathematics of modern physics seemed to describe a way that two widely separated points (perhaps light years apart) might be connected in such a way that something could pass between the two points without crossing the intervening space. The math involved describes a universe with more than the three dimensions we live in. in our 3-d universe, you need three coordinates (or points) to describe a particular location. If you have more dimensions (which our universe probably does) you need more reference points/coordinates. In the Stargate "universe" the idea ws that there were six dimensions (actually seven -- the TV series posited that the star gate could move you in time as well as space, adding another dimension). Now-- the real physics: A wormhole is (at this time) purely a theoretical phenomenon. No one has ever created or detected one. Physicists don't even know if one can exist --only that there is nothing we know that says one can't. Also, we do not know what one would be like if it is possible. A wormhole might be nothing but a short-term event at the atomic level. or it might be like the wormholes in "Star Treck Voyager" -- or like the Star gate. Your guess is as good s anyone else's. BTW: a tip about the Pythagorean theorem: C^2 = A^2 + B^2. To be precise (essential in mathematics) describes the relative lengths o fthethree sides of a right triangle (one with one angle that qual s90 degrees). Example: if side A is 3 inches and side B is 4 inches, plug in those numbers and you get the length of the third side (c) which here is 5 inches. Now, here's why this is important. What I wrote in the previous paragraph is all there is to the Pythagorean teorem itself. BUT (trumpets, plese) it turns out that it is the key -- the starting point -- for trigonometry. That is a VERY big deal for very practical reasons. Using mathematics derived from the Pythagorean theorem, you can indeed determine the location of a point using any two othe rpoints -- with one qualification. Any three points form a triangle -- an dyou also have to know (or measure) at least one of the angles o fthe triangle. The practical value: trigonometry is the tool used for navigation (ships, plaes, ec), to make accurate maps, to design buildings, to calculate any trajectory from a bullet t a spacecraft. Plus a lot mroe. Including wormholes, if there are any (granted, the math required for extra dimensions gets VERY complicated!).

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