How do you solve these problems : 20x - 40xy and 28x^2 y^2 - 49x^2 y?
Topic: How do you solve these problems : 20x - 40xy and 28x^2 y^2 - 49x^2 y?
June 26, 2019 / By Beatrix Question:
I need to know the steps and the answer for these problems:
20x - 40xy = ??
28x^2 y^2 - 49x^2 y = ??
I know it might be a dumb question but I have forgotten algebra!! :-D I am helping my sister with her homework and I have not done this kind of stuff in years and I have completely forgotten how to do these types of problems. If someone could please help me out without being rude that would be great! THANKS!! :) Also, ^2 means squared. Like the little 2 in the upper corner. Hehe thanks!
I messed up the first equation :( it is supposed to be 24x - 40xy! I'm sorry. I don't know how I missed that. So it is 24x not 20x. Thanks again! :)
Best Answers: How do you solve these problems : 20x - 40xy and 28x^2 y^2 - 49x^2 y?
Adena | 6 days ago
What is this, is this a factoring, well let assume that it is a factoring:
Using the distributive property, we can solve this problem.
Find the common factor of each term and put it outside.
Common factor: 20x
20x - 40xy = 20x(1 - 2y)
Common factor: 7x^2 y
28x^2 y^2 - 49x^2 y = 7x^2 y(4y - 7)
👍 220 | 👎 6
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Originally Answered: Does anyone know how to solve these problems? Please solve for each variable. show work if possible.?
1) Subtract 12x from each side
-3x = 6
Divide each side by -3
x = -2
2) Simplify the parentheses part first.
-2y - 6y + 3 = 6y - 4
Combine like terms
-8y + 3 = 6y - 4
Subtract 6y from each side and subtract 3 from each side
-14y = -7
Divide both sides by -14 and reduce.
y = -7/-14
y = 1/2
Now try the others on your own.
Remember you can always check your answer by replacing the variable with the answer you just got to see if you get a true equation.
The best way to learn math is to do the problems yourself.
20x - 40xy factors by dividing out a GCF of 20x from each term:
20x - 40xy =
20x(1 - 2y) <==ANSWER
28x²y² - 49x²y factors by dividing out a GCF of 7x²y from each term:
7x²y(4y - 7) <==ANSWER
I hope that helps!! :-)
👍 90 | 👎 -1
These are clearly simultaneous equations. I could solve them in time but I'm a bit too sleepy right now sorry.
Basically, you isolate a variable (say, x) in the first equation (e.g. leaving it in the form x = ???).
You then substitute this value of x into the second equation and simplify.
I think that in this case it might require long division of polynomials: if I'm right, google it and you'll get the method of how to do it.
You should be left at most with a quadratic equation in one variable to solve.
👍 85 | 👎 -8
i know how to solve the first one but not the second sorry.
i hope it's not wrong but truthfully i am not sure but this is how i remember solving these kinda problems
👍 80 | 👎 -15