6367 Shares Topic: Please! help me with my math! please!?
June 16, 2019 / By Braidy
Question: On a separate piece of paper, solve each system by graphing. Is (–2, 3) the solution of each system? 1. x + y = 1 x = –2 yes no 2. y = 2x + 7 x = y – 4 yes no Solve by graphing. Tell whether the system has one solution, no solution, or infinitely many solutions. 3. y = x + 3 y = –2x + 3 A.one solution B.no solution C.infinitely many solutions 4. y = x + 2 –4x + y = –1 A.one solution B.no solution C.infinitely many solutions 5. y – 4 = 2x y – 2x = 4 A.one solution B.no solution C.infinitely many solutions 6. 2 + y = 2x y – 2x = 5 A.one solution B.no solution C.infinitely many solutions Solve each system using substitution. 10. y = 5x y – x = 8 A.(2, –10) B.(2, 10) C.(–2, 10) 11. 2x = 3y x + 2y = 7 A.(3, 2) B.(–3, 2) C.(–3, –2) Solve each system by elimination. 12.5x + 4y = 1 3x – 4y = 7 A.(–1, –1) B.(1, –1) C.(1, 1)  Albina | 8 days ago
Just out of random curiosity, how are we supposed to "solve by graphing" on YA!? Even if I could, luv, I wouldn't do 12 problems for you. Try being a bit more reasonable.
👍 164 | 👎 8 Originally Answered: I have a math emergency. I do not understand any of my online math class. It is advanced. Can anyone help me?
I'm not sure how you are to draw graphs online. However... To do this, draw two graphs with two axis. On each graph label the horizontal axes "x" and the veritcal axis "f(x)" Now for a on the first graph Pick a number for x, say 0 and plug it in for x... to get f(x)=-3*0+7=7. Your first point will be (0,7) if you pick 0 for x. Find the point (0,7) on the graph by going up 7 points on the f(x) axes and puting a point there. Label this point "(0,7)". Now pick another number for x. For example 2. Plug it in for x to get f(x)=-3*2+7=1. Your second point will be (2,1) if you pick 2 for x. Find the point (2,1) on the graph by going out 2 points on the x axes and up 1 points on the f(x) axes and puting a point there. Label this point "(2,1)". Using a straight edge draw a line through both points extending out eather direction past these points. Put an arrow on each of the line to indicate the line goes forever in both directions. Label the line "f(x) = –3x + 7." The second one is a little more complicated because it is a parabola instead of a straight line. First you want to find the center vertex of the parabola. To do this it's easier if you put the equation in the form... f(x)=a(x-b)^2+c when in this form the vertex will be (b,c) to do this first factor a three so you have ... -3(x^2-x/3+5/3) Now complete the square... -3(x^2-x/3+1/36-1/36+5/3) Leaving us with -3(x-1/6)^2-3*(-1/36+5/3) f(x)=-3(x-1/6)^2+1/12-5 f(x)=-3(x-1/6)-59/12 now with this info we can see that the vertex is at (1/16,59/12) put a point here and label it. Then pick two points to either side by plugging in numbers for x and getting f(x) out and label them. Go through one point toward the vertex and change directions at the vertex and go through the other point. (Rough sketch) Put arrows on either end of the line to show they go on for ever. Both ends should be pointed downward. Label the line with the equation. You are done. Originally Answered: I have a math emergency. I do not understand any of my online math class. It is advanced. Can anyone help me?
because the first graph has only x raised to the first power it is linear equation; the graph will be a line so all you need is two points. Pick any two values for x then solve for y If you pick x = 0 and x = 2 your points would be y = -3*0 + 7 = 7 . . . . ( 0 , 7 ) y = -3*2 + 7 = 1 . . . . ( 2 , 1 ) B) the second equation has an x^2 so its graph will be a parabola which looks like a U; however because the coefficient os x^&2 is negeative, it will be upside down like this ∩ the point where it turns is called the vertex the vertex is (1/6 , - 59/12) you may just want to plot some points, here are some (-1, -9) (0, -5_ (1, -7) Originally Answered: I have a math emergency. I do not understand any of my online math class. It is advanced. Can anyone help me?
This is simple. Just tabulate the values for x and f(x), then draw them in a piece of paper. Let's do the first one. It is a straight line because the highest exponent is 1. So a straight line needs only two points to be fully defined at x = 0, f(x) = 7 (try and see) at x = 1, f(x) = 4 (again, try and see) Grab a checkered piece of paper, draw the Cartesian axis, label the horizontal line X and the vertical line Y or f(x). Then go and draw a point in x=0, y=7, then another point in x=1, y=4. Finally, join the points with a straight line! The second one is a parabola (the highest coefficient is 2) It will curve up or down... try that one yourself. Trey
Just wandering if you are just wanting answers or help? 1. x=2 y=3 2. -2=2(3) +7 3 - 6 I don't get were you are getting extra numbers can you explain more 10. B 11. A 12 B
👍 60 | 👎 1 Originally Answered: 3 Math Homework Questions HELP! Math Question 10 points?
Cost of an apple (y) in terms of cost of an orange (x)—2 equations: 4x + 5y = \$3.56 y = (\$3.56 - 4x)/5 3x + 4y = \$2.76 y = (\$2.76 - 3x)/4 Cost of an orange—x: 4(\$3.56 - 4x) = 5(\$2.76 - 3x) \$14.24 - 16x = \$13.80 - 15x x = \$0.44 Cost of an apple—1st equation: = (\$3.56 - 4[\$0.44])/5 = (\$3.56 - \$1.76)/5 = \$1.80/5 or \$0.36 Answer: orange, \$0.44; apple, \$0.36 ----------- No. of student tickets sold—x: \$4.50x + \$9.00(200 - x) = \$1,485.00 x + 2(200 - x) = 330 x + 400 - 2x = 330 x = 70 No. of adult tickets sold: = 200 - 70 = 130 Answer: 70 student tickets; 130 adult tickets ----------- No. of tickets of those who held activity cards—x: \$2.50x + \$4.00(203 - x) = \$620.00 5x + 8(203 - x) = 1,240 5x + 1,624 - 8x = 1,240 3x = 384 x = 128 No. of tickets of those who didn't hold activity cards: = 203 - 128 = 75 Answer: with activity cards, 128; without activity cards, 75 Originally Answered: 3 Math Homework Questions HELP! Math Question 10 points?
I'm not going to give you the answers, because then you won't learn anything. But I'll explain HOW to do each problem. For each one, you should first write an equation for each fact the problem gives you, and then use substitution to find one value and then the other. For problem one, you are told that four oranges and five apples cost \$3.56. In other words, four times the cost of an orange plus five times the cost of an apple is \$3.56. So, 4x + 5y = 3.56. For the second part, do the same thing and you get 3x + 4y = 2.76. Now just use substitution and the rest should be easy. Problem two is even easier. You know there are two types of tickets sold, and 200 were sold in total. So, if x is student tickets and y is adult, x + y = 200, and 4.5x + 9y = 1485. Finally, problem three is the same thing as problem 2. x + y = 203, and 2.5x + 4y = 620. I hope that helps. Next time, it would be more helpful if you explained what you didn't understand, instead of trying to use Yahoo Answers to cheat, and therefore not learn the material, which you really SHOULD learn if you want to be a competent human being.