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# Anyone can help me solve these algebra problems?

Topic: Anyone can help me solve these algebra problems?
June 16, 2019 / By Coco
Question: 1.) Solve: D = 4/5( mx - mb ) for m, I think is m = 5D / 4( x - b ), but not sure. 2.) Solve the inequality: -28 <= -5x + 2 <= -13, my answer is [3 , 6] 3.) Solve the inequality: 6x - 4 > 5x - 8, my answer (-4 , infinity) 4.) Solve for x: 1/8(x + 16) + 1/5(x + 5) = x + 2, my ans: 40/27 5.) Solve for x: x/6 - 4 = x/3 - 3, my ans: - 6 6.) Solve for x: (x - 2) / 3 - (x - 3) / 6 = (3 - x) / 2 - 3, my ans: - 2? 7.) A small company that makes hand-sewn leather shoes has fixed costs of \$320 a day, and total costs of \$1200 per day at an output of 20 pairs of shoes per day. Assume that total cost C is linearly related to output x. Find an equation of the line relating output to cost. Write the final answer in the form C = mx + b Ans: C = 60x + 320 It will be great will anyone can confirm my answer, will grant the 10 pts immediately, thanks.

## Best Answers: Anyone can help me solve these algebra problems?

Belle | 6 days ago
D = 4/5( mx - mb ) first factor out m d=4/5m(x-b) multiply each side by 5/4 5d/4 = m(x-b) and divide each side by (x-b) (5d)/4(x-b) = m Yup, you've got it! -28 ≤ -5x+2 ≤ -13 so subtract 2 from each section -30 ≤ -5x ≤ -15 divide each section by -5. Remember to change the direction of the inequality sign since you're dividing by a negative number 6 ≥ x ≥ 3 So yes, x ≤ 6 and x ≥ 3 Nice catch on the brackets too! Attempting number 6: [(x - 2) / 3] -[( x - 3) / 6] = [(3 - x) / 2] -3 I hope that's right! These are fractions, so you need a common denominator. You have as denominators 3, 6, and 2 so the LCD is 6. Convert the fractions: [2/2(x - 2) / 3] -[( x - 3) / 6] = [3/3(3 - x) / 2] -6/6(3) multiply [(2x - 4) / 6] - [(x - 3)/ 6] = [(9 - 3x) / 6] - 18/6 When working with fractions with common denominators, we only work the numerators; the denominators remain unchanged. Since there are no variables in the denominators, we can eliminate them from our equation (same as multiplying everything by the common denominator): (2x - 4) - (x - 3) = (9 - 3x) - 18 Distribute the - to (x - 3): 2x - 4 - x + 3 = 9 - 3x - 18 Combine like terms: x - 1 = -3x - 9 add 3x to each side 2x - 1 = -9 add 1 to each side 2x = -8 divide each side by 2 x = -4 So either you dropped a sign somewhere or I didn't copy it down correctly. If that's the case, use my steps and check your work again.
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Originally Answered: How do you solve these two algebra problems?
subtracting 1st from 2nd... 0=x^2+18x+59 answers will come in roots....use calculator put the values for x in any of the equations n get the values for y
Originally Answered: How do you solve these two algebra problems?
finding Discriminant for 1 u get -4 it means they have imaginary roots.u get irrational roots for 2.
Originally Answered: How do you solve these two algebra problems?
listen very carefully. break in to your school and steal the teachers book. near the index there should be a list of answers. Hope this helps!