2613 Shares

Anyone can help me solve these algebra problems?

Anyone can help me solve these algebra problems? Topic: Anyone can help me solve these algebra problems?
June 16, 2019 / By Coco
Question: 1.) Solve: D = 4/5( mx - mb ) for m, I think is m = 5D / 4( x - b ), but not sure. 2.) Solve the inequality: -28 <= -5x + 2 <= -13, my answer is [3 , 6] 3.) Solve the inequality: 6x - 4 > 5x - 8, my answer (-4 , infinity) 4.) Solve for x: 1/8(x + 16) + 1/5(x + 5) = x + 2, my ans: 40/27 5.) Solve for x: x/6 - 4 = x/3 - 3, my ans: - 6 6.) Solve for x: (x - 2) / 3 - (x - 3) / 6 = (3 - x) / 2 - 3, my ans: - 2? 7.) A small company that makes hand-sewn leather shoes has fixed costs of $320 a day, and total costs of $1200 per day at an output of 20 pairs of shoes per day. Assume that total cost C is linearly related to output x. Find an equation of the line relating output to cost. Write the final answer in the form C = mx + b Ans: C = 60x + 320 It will be great will anyone can confirm my answer, will grant the 10 pts immediately, thanks.
Best Answer

Best Answers: Anyone can help me solve these algebra problems?

Belle Belle | 6 days ago
D = 4/5( mx - mb ) first factor out m d=4/5m(x-b) multiply each side by 5/4 5d/4 = m(x-b) and divide each side by (x-b) (5d)/4(x-b) = m Yup, you've got it! -28 ≤ -5x+2 ≤ -13 so subtract 2 from each section -30 ≤ -5x ≤ -15 divide each section by -5. Remember to change the direction of the inequality sign since you're dividing by a negative number 6 ≥ x ≥ 3 So yes, x ≤ 6 and x ≥ 3 Nice catch on the brackets too! Attempting number 6: [(x - 2) / 3] -[( x - 3) / 6] = [(3 - x) / 2] -3 I hope that's right! These are fractions, so you need a common denominator. You have as denominators 3, 6, and 2 so the LCD is 6. Convert the fractions: [2/2(x - 2) / 3] -[( x - 3) / 6] = [3/3(3 - x) / 2] -6/6(3) multiply [(2x - 4) / 6] - [(x - 3)/ 6] = [(9 - 3x) / 6] - 18/6 When working with fractions with common denominators, we only work the numerators; the denominators remain unchanged. Since there are no variables in the denominators, we can eliminate them from our equation (same as multiplying everything by the common denominator): (2x - 4) - (x - 3) = (9 - 3x) - 18 Distribute the - to (x - 3): 2x - 4 - x + 3 = 9 - 3x - 18 Combine like terms: x - 1 = -3x - 9 add 3x to each side 2x - 1 = -9 add 1 to each side 2x = -8 divide each side by 2 x = -4 So either you dropped a sign somewhere or I didn't copy it down correctly. If that's the case, use my steps and check your work again.
👍 260 | 👎 6
Did you like the answer? Anyone can help me solve these algebra problems? Share with your friends
Belle Originally Answered: How do you solve these two algebra problems?
subtracting 1st from 2nd... 0=x^2+18x+59 answers will come in roots....use calculator put the values for x in any of the equations n get the values for y
Belle Originally Answered: How do you solve these two algebra problems?
finding Discriminant for 1 u get -4 it means they have imaginary roots.u get irrational roots for 2.
Belle Originally Answered: How do you solve these two algebra problems?
listen very carefully. break in to your school and steal the teachers book. near the index there should be a list of answers. Hope this helps!

Adria Adria
you will possibly desire to be sure how briskly he is going, Miles in line with hour like, So what proportion cases can 8 pass into 464? which will inform you the MPH, then multiply that by capacity of 5 a million/2. same with the 2d question, this is an identical thought.
👍 110 | 👎 -1

Adria Originally Answered: How would you solve this Algebra 1 problems?
Side length of a square = square root of total square yards. Side length = square root of 1620 = 40 yards.
Adria Originally Answered: How would you solve this Algebra 1 problems?
The equation for the area of a square is base (b) times height (h). Since it is square, b=h b*h=1620 So the square root of 1620 is the answer. 40

If you have your own answer to the question Anyone can help me solve these algebra problems?, then you can write your own version, using the form below for an extended answer.