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How to solve this 3 chemistry problems?

How to solve this 3 chemistry problems? Topic: How to solve this 3 chemistry problems?
June 16, 2019 / By Colleen
Question: Okay so am stuck with this four problems someone please help! thank you 1. 444 000 mL = ? kL 2.204.7 mm = ? cm 3. 3400 mm = ? km
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Best Answers: How to solve this 3 chemistry problems?

Bernadette Bernadette | 4 days ago
here are 2 videos that show you how to do these problems yourself http://www.kentchemistry.com/links/Measu...
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Bernadette Originally Answered: Help with chemistry problems don't know how to solve them?
(7.06g) + (1.2 x 10^-4 kg) convert to common units - I choose kg 7.06E-3 kg + 1.2E-4 kg convert lower power to the higher 7.06E-3 kg + 0.12E-3 kg = 7.18E-3 kg (5.36 x 10^-1 kg) - (7.40 x 10^-2 kg) convert lower power to the higher 5.36E-1 - 0.740E-1 = 4.62E-1 or 0.462 kg convert 6800 cm to km 6800 cm * 1 m/100 cm * 1 km/1000 m = 0.068 km convert 25 kg to Mg are those mega grams? if so 25 kg * 1000 g/kg * 1 Mg/ 1E6 g = 0.025 Mg

Aeron Aeron
Basic unit conversion. Use the unit-factor method with the appropriate conversion factors. Set up the conversion factors to cancel out the units you don't want and leave the units you do. 4.44x10^5 mL x (1L / 1000mL) x (1 kL / 1000L) = 0.444 kL 204.7 mm x (1 cm / 10mm) = 20.47 cm 3400 mm x (1m / 1000 mm) x (1 km / 1000 m) = 0.0034 km
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Thane Thane
If #1 is supposed to be 444.000 mL, then the answer is 0.000444000 kL. If #1 is supposed to be 444,000 mL, then the answer will be 0.444000 kL. #2) 204.7 mm=20.47 cm #3) 3400 mm=0.0034 km This is all about maintaining significant digits.
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Preston Preston
just simple conversion you can do with dimensional analysis. 1. 444,000mL x 1L/1,000mL x 1kL/ 1,000 L 2. 204.7 mm x 1cm/10mm= 3. 3400mm x 1m/1000mm x 1km/1000m=
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Preston Originally Answered: Anyone like chemistry/ math? I need someone to help solve some of these problems for me [=?
First calculate the change in temperature Change in temp of water =40.1 C -26.7 C =13.4 C Change in temp of iron =40.1 C –150.0 C =-109.9C Symbols shown in brackets (C is specific heat, M the mass and T change in temperature) check your formula for correct symbols (subscript shows the substance c for calorimeter, m for metal and w for water) -(CcMcTW)= CMMMTM +MwCwTw AND Then Cc =( -CMMMTM –MwCwTw)/(TwMc) Then heat capacity of glass calorimeter (Cc) = (-(0.4521 J/g C x 245.0 g x-109.9C) –(200.0 g x4.18 J/g C x 13.4 C))/ (13.4 C * 4.5g)= 16.096 J/g C Hope it helps, just check calculations and whether you have the same formula, I used comp calculator

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