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# Need math help, im stumped?

Topic: Need math help, im stumped?
July 20, 2019 / By Dawn
Question: I am stuck on the following problems from my hw.. please read the problem carefully, to avoid the same mistakes I did.... the number is 4 http://i35.tinypic.com/2wqa6g9.jpg thank very much [:

## Best Answers: Need math help, im stumped?

Brett | 1 day ago
Hello =)! To solve this question you have to know something called Patagonian theorem. This theorem states the following formula; diagonal= (√x^2 + y^2) So analyze the square or rectangle given ; when you make a diagonal across you make a triangle right that what the base times height represents the x and y accordingly; for A). a square 10 cm each side diagonal = √10^2 + 10^2 diagonal = aprox 14.4 cm for B) so s treat this as a number diagonal = √s^2 + s^2 diagonal = √(2s)^(2) for C) a rectangle 10 by 24 cm diagonal = √ 10^2 + 24^2 diagonal = 26 for D) diagonal = √m^2 + n^2 Hope this helps !
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Originally Answered: Not trying to get anyone to do my homework, but seriously stumped here. anyone willing to help me out? Math!
A little note in the beginning: you can write mathematics formulas in line inputs like this: (12x^3 / 6x^-2)^2. You can add extra parentheses to clarify it: ((12 x^3) / (6 x^-2))^2. People are quite used to this. If I understood the formula correctly, here's the easiest way how to proceed: Turn the x^-2 "upside down" to get ((12 x^3 x^2)/6)^2 Put the powers together to get ((12 x^5)/6)^2 Divide both sides of the fraction by 6 to get (2 x^5)^2 Finally, after these simplifications, take the power ^2: 4 x^10. I hope this is what you wanted because the only difference of my result to yours is in the exponent of x. You made a mistake when computing (12x^3)^2: in (x^3)^2, the powers are multiplied: (x^3)^2 = x^(3*2) = x^6.
Originally Answered: Not trying to get anyone to do my homework, but seriously stumped here. anyone willing to help me out? Math!
I get 24x^8 as the answer. (I am assuming that the (12x^3) is raised to the second power, not just multiplied by 2) First of all, you don't turn the whole fraction upside down because the negative exponent in your problem is only in the denominator. You can deal with negative exponents by taking the part that is raised to a negative exponent and moving it across the division bar, then get rid of the negative. So, the only part of your problem that moves across the division bar is the x^-2 in the denominator. Just move it to the numerator and make it x^2. After you do this, your expression should look like: [(12x^3)^2] * [x^2] / 6 (Since the 6 in the denominator was not raised to the -2 power, it just stays in the denominator) To simplify the numerator, you got the 12^2 = 144 part right, but when you raise a power to a power, you multiply the exponents, not add, so (x^3)^2 is equal to x^6 (not x^5) After taking those two steps, you should have: [144x^6] * [x^2] / 6 Now, when you multiply powers with the same base, that is when you add the exponents, so [x^6] * [x^2] = x^8 (A good way to think of this is seeing that x^6 = x*x*x*x*x*x and x^2 = x*x, so when you multiply them you get [x*x*x*x*x*x] * [x*x], which is 8 x's multiplied together, or x^8) After that step, you should have: [144x^8] / 6 Now just simplify the 144/6, which equals 24 and you have your answer: 24x^8
Originally Answered: Not trying to get anyone to do my homework, but seriously stumped here. anyone willing to help me out? Math!
the idea of how to treat the minus exponentis basically correct, but you didn't do it correctly. As a start: ... (12x^3)2 = 12*12*x^6, this is ok 6x^-2 becomes 6/(x^2): the exponent is only on the x (unless there is a parenthesis missing on the one you posted). Since this was i a -over- you multiply by the inverse, and get 1/(6/(x^2))=(x^2)/6 So it become 12*12*x^6 * x^2 /6, that is 24x^8 Clear?

Alexina
Equation writing time :) \$2.seventy 5 is your finished. Nickels are extremely worth \$0.05, dimes are extremely worth \$0.a million, and quarters are extremely worth \$0.25. we are going to use the variables N, D, and Q to signify the kind of nickels, dimes, and quarters we've. So, 2.seventy 5=.05N+.1D+.25Q you're additionally given the numbers of each and every kind of coin regarding eachother. Now you 2 greater equations: N=a million/2Q, and D=2Q-a million (tell me in case you don't be responsive to how I have been given those) Use the substitution theory to sub in a million/2Q and 2Q-a million for N and D. Now your first equation reads: 2.seventy 5=.5(a million/2Q)+.a million(2Q-a million)+.25Q considering the fact which you in basic terms have a million variable, you could circulate forward and sparkling up for Q. (distribute the .5 and .a million, combine like words, subtract and upload stuff to the two factors) once you have the kind of quarters (Q), you could plug that type into the 2nd and third equations we discovered to locate the N and D, which characterize the kind of nickels and the kind of dimes respectively.
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